Question

tgx>-√3 срочно !!!!!!!!

Answer 1

$tgx>-\sqrt{3}\\\\arctg(-\sqrt{3})+\pi n<x<\frac{\pi }{2}+\pi n,nez\\\\-\frac{\pi }{3}+\pi n <x<\frac{\pi }{2}+\pi n,nez$

x ∈$(-\frac{\pi }{3}+\pi n;\frac{\pi }{2}+\pi n),nez$