Question

Сколько будет

log⁴ log³ 9,

Log125/log5,

Log6 12 - log6 3 + log6 9.

Answer 1

$1)log_{4}log_{3}9=log_{4}2=\frac{1}{2}log_{2}2=0,5\\\\2)\frac{lg125}{lg5}=\frac{lg5^{3} }{lg5}=\frac{3lg5}{lg5}=3\\\\3)log_{6}12-log_{6}3+log_{6}9=log_{6}\frac{12*9}{3}=log_{6} 36=2$