Question

Помогите решить 4 номер. Срочно

Answer 1

$frac{\frac{(9a^{4})^{5}*(3a)^{6}}{(27a^{6})^{4}}=\frac{(3^{2}*a^{4})^{5}*(3a)^{6}}{(3^{3}*a^{6} )^{4}}=\frac{3^{10}*a^{20}*3^{6}*a^{6}}{3^{12}*a^{24}}=3^{10+6-12}*a^{20+6-24}=3^{4} *a^{2}=81a^{2}$

Answer 2

=9а$(9a^{20}*3a^{6} ) /27a^{24}= 27a^{26}/27a^{24}=a^{2}=(2/3)^{2}=4/9=0,4$