Question

сократить дробь. плиз

Answer 1

$5x^{2}+12x+4=0\\\\D=12^{2}-4*5*4=144-80=64=8^{2}\\\\x_{1}=\frac{-12+8}{10}=-0,4\\\\x_{2}=\frac{-12-8}{10}=-2\\\\5x^{2}+12x+4=5(x+0,4)(x+2)=(5x+2)(x+2)\\\\\frac{5x+2}{5x^{2}+12x+4 }=\frac{5x+2}{(5x+2)(x+2)}=\frac{1}{x+2}$