Question

Помогите, пожалуйста, решить уравнения

Answer 1

$\sqrt[3]{24 + \sqrt{ {x}^{2} + 5 } } = 3\\ 24 + \sqrt{ {x}^{2} + 5} = 27 \\ \sqrt{x {}^{2} + 5} = 27 - 24 = 3 \\ {x}^{2} + 5 = 9 \\ {x}^{2} = 4 \\ x1 = 2 \\ x2 = - 2$
$\sqrt{11 - \sqrt[3]{ {x}^{2} + 7 } } = 3 \\ 11 - \sqrt[3]{ {x}^{2} + 7} = 9 \\ \sqrt[3]{ {x}^{2} + 7 } = 2 \\ {x }^{2} + 7 = 8 \\ {x}^{2} = 1 \\ x1 = 1 \\ x2 = - 1$
$5 - x - \sqrt{x + 7} = 0 \\ 5 - x = \sqrt{x + 7} \\ 25 - 10x + {x}^{2} = x + 7 \\ {x }^{2} - 11x + 18 = 0 \\ x1 = 9 \\ x2 = 2$
x1 не подходит. т. к х<=5