Question

Помогите пожалуйста!

Answer 1

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Answer 2

tg225° * Cos330° * Ctg120° * Sin240° = tg(180° + 45°) * Cos(360° - 30°) *

* Ctg(180° - 60°) * Sin(180° + 60°) = tg45° * Cos30° *(-  Ctg60°) * (- Sin60°) =

$=1*\frac{\sqrt{3} }{2}*\frac{\sqrt{3} }{3}*\frac{\sqrt{3} }{2}=\frac{\sqrt{3} }{4}$