Question

Помогите очень прошу решить уравнение!!!

Answer 1

$2 {x}^{2} - 5x + 3 = 0 \\ \\ d = {b}^{2} - 4ac = ( - 5)^{2} - 4 \times 2 \times 3 = \\ \\ = 25 - 24 = 1 \\ \\ x 1= \frac{ - b + d}{2a} = \frac{ 5 + 1}{2 \times 2} = \frac{6}{4} = 1\frac{2}{4} = 1 \frac{1}{2} \\ \\ x2 = \frac{ - b - d}{2a} = \frac{5 - 1}{4} = 1$

Готово.