Question

4x^2-(x+1)^2=0 помогите решить уравнение

Answer 1

a^2 - b^2 = (a - b)(a + b)

4x^2 - (x + 1)^2 = 0

(2x)^2 - (x + 1)^2 = 0

(2x - x - 1)(2x + x + 1) = 0

(x - 1)(3x + 1) = 0

x=1

x=-1/3