Question

2^(5-2n)*5^(3n+1)*2^(n-3)*5^(7-n)

Answer 1

a^b*a^c = a^(b+c)

2^(5-2n)*5^(3n+1)*2^(n-3)*5^(7-n) = 2^(5-2n)*2^(n-3)  *  5^(3n+1)*5^(7-n)

= 2^(5 - 2n + n -3) * 5^(3n + 1 + 7 - n) = 2^(2 - n) * 5^(2n + 8)

Answer 2

2^(5-2n+n-3)*5^(3n+1+7-n)=2^(2-n)*5^(2n+8)=2^(2-n)*25^(n+4)=2^2/2^n*25^n*25^4=(2^2*25^n*25^4)/(2^n)=2^2*625^2*12,5^n=1250^2*12,5^n=1562500*12,5^n