Question

Помогите, пожалуйста.
10х/25-х²– 1/5+х – 1/х-5 = 0

Answer 1

$\frac{10x}{25 - {x}^{2} } - \frac{1}{5 + x} - \frac{1}{x - 5} = 0 \\ \frac{10x}{(5 - x)(5 + x)} - \frac{1}{5 + x} + \frac{1}{5 - x} = 0 \\ \frac{10x - 5 + x + 5 + x}{(5 - x)(5 + x)} = 0 \\ 12x = 0 \\ x = 0$
и x ≠ ±5