Question

6 sin²x + 6 sin2x = 0

Answer 1

6Sin²x + 6Sin2x = 0

Sin²x + Sin2x = 0

Sin²x + 2SinxCosx = 0

Sinx(Sinx + 2Cosx) = 0

1) Sinx = 0

x = πn, n ∈ Z

2) Sinx + 2Cosx = 0

Разделим почленно на Cosx ≠ 0 , получим :

tgx + 2 = 0

tgx = - 2

x = arctg(-2) + πn , n ∈ Z

x = - arctg2 + πn , n ∈ Z