Question

решите систему уравнений

Answer 1

$\displaystyle \tt {} \ \left\{ \begin{array}{ccc} \tt 2x-y=-11 \ \\\\ \tt \dfrac{x-1}{2}+\dfrac{y}{3}=2\end{array} \Leftrightarrow \left\{ \begin{array}{ccc} \tt y=2x+11 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\\\ \tt \dfrac{3\cdot(x-1)+2\cdot(2x+11)}{6}=2\end{array}$

$\displaystyle \tt {} \ \ \ \ \ 3x-3+4x+22=12\\\\{} \ \ \ \ \ 7x=12-19\\\\{} \ \ \ \ \ x=-1 \ \ \ \ \ \ \ \ \ \ \ \ y=2\cdot(-1)+11=11-2=9$

Ответ: {-1; 9}

Answer 2

Ответ:

Пошаговое объяснение:

2x-y=-11

(x-1)/2+y/3=2

y=2x+11

(x-1)/2+(2x+11)/3=2

1/2x-1/2+2/3x+11/3=2

1/2x+2/3x+11/3-1/2=2

3/6x+4/6x+22/6-3/6=2

7/6x+19/6=12/6

7/6x=12/6-19/6

7/6x=-7/6

7x=-7

x=-7/7

x=-1

y=2*(-1)+11

y=-2+11

y=9