Question

1) $\frac{14m^{4} p}{n^{6} } * \frac{n^{5} }{35mp^{4} }$
2) $\frac{3x - 15}{x+3} : \frac{x^{2} - 25 }{3x + 9}$

Answer 1

1)

$\frac{14m^{4} p}{n^{6} } \cdot \frac{n^{5} }{35mp^{4} }=\frac{2m^3}{5np^3}$

2)

$\frac{3x - 15}{x+3} : \frac{x^{2} - 25 }{3x + 9}=\frac{3(x-5)}{x+3}\cdot \frac{3(x +3)}{(x-5)(x+5)}=\frac{9}{x+5}$