Question

Помогите,пожалуйста,буду признателен.

Answer 1

$log_{\sqrt{3}} \frac{1}{3}-log_{0.2}5+log_{64}4=-2+1+\frac{1}{3}=-\frac{2}{3}$

$3^{log_{2}\frac{1}{4}+log_{3}5}=3^{log_{2}\frac{1}{4}}\cdot3^{log_{3}5}=3^{-2}\cdot5=\frac{1}{9}\cdot5=\frac{5}{9}$

$7^{log_{7}2} :log_3\frac{1}{9}=2:(-2)=-1$

$11^{log_{11\sqrt{11}}125-log_{121}9}=11^{\frac{2}{3}log_{11}5^3-log_{11}3}=11^{log_{11}25-log_{11}3}=11^{log_{11}25}:11^{log_{11}3}=\frac{25}{3}=8\frac{1}{3}$