Question

сделайте всё срочно надо плиз

Answer 1

2 вариант на фото. Удачи!!!
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▪1 вариант:

$1) \: \: \: {m}^{3} - {n}^{3} = (m - n)( {m}^{2} + mn + {n}^{2} ) \\ 2) \: \: \: {c}^{3} + 8 = (c + 2)( {c}^{2} - 2c + 4) \\ 3) \: \: \: 27 {a}^{3} - {b}^{3} = (3a - b)(9 {a}^{2} + 3ab + {b}^{2} )$
$4) \: \: \: {125}^{3} + {a}^{3} {b}^{3} = (5 + ab)( 25 - 5ab + {a}^{2} {b}^{2} )$
$5) \: \: \: {x}^{6} - {y}^{9} = ({x}^{2} - {y}^{3} )( {x}^{4} + {x}^{2} {y}^{3} + {y}^{6} ) \\ 6) \: \: \: 1000 {a}^{12} {b}^{3} + 0.001 {c}^{9} {d}^{12} = {(10 {a}^{4} b)}^{3} + {(0.1 {c}^{3} {d}^{4} )}^{3} = (10 {a}^{4} b + 0.1 {c}^{3} {d}^{4} )(100 {a}^{8} {b}^{2} - {a}^{4} b {c}^{3} {d}^{4} + 0.01 {c}^{6} {d}^{8} )$
$7) \: \: \: 4 - 36 {a}^{2} = (2 - 6a)(2 + 6a) \\ 8) \: \: \: 400 - 121 {c}^{2} = (20 - 11c)(20 + 11c)$
$9) \: \: \: 49 {x}^{2} - 121 {a}^{2} = (7x - 11a)(7x + 11a) \\ 10) \: \: \: 4 {y}^{2} - 12y + 9 = {(2y - 3)}^{2} = (2y - 3)(2y - 3) \: \\ 11) \: \: \: 9 {m}^{2} + 24 m + 16 = {(3m + 4)}^{2} \\ 12) \: \: \: {p}^{2} + 10pq + 25 {q}^{2} = {(p + 5q) }^{2}$