Question

решите систему уравнений пожалуйста!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

х=1-4у

$\frac{3}{1-4y} +\frac{2}{y} =1\\ \\ \frac{3y+2-8y}{y-4y^{2} } =1\\ \\ -5y+2=y-4y^{2} \\ \\ 4y^{2} -6y+2=0\\ \\ 2y^{2} -3y+1=0\\ \\ d=9-8=1\\ \\ y1=3-1/4=2/4=1/2\\ \\ y2=1\\ \\ \\ x1=1-4*1/2=-1\\ \\ x2=1-4*1=-3$