Question

При каких значениях а значение двучлена равно нулю?

Answer 1

$4 {a}^{2} + 12a = 0 \\ 4a(a + 3) = 0 \\ a1 = 0 \\ a + 3 = 0 \\ a2 = - 3$
$4.5 {a}^{2} - 0.9a = 0 \\ 0.9a(5a - 1) = 0 \\ a1 = 0 \\ a2 = \frac{1}{5}$
${5}^{2} + 10a = 0 \\ 10a = - 25 \\ a = - 2.5$
$4.2 {a}^{2} - 0.6a = 0 \\ 0.6a(7a - 1) = 0 \\ a1 = 0 \\ a2 = \frac{1}{7}$

Answer 2

1) 4а2+12а
3а(а+4)
3а=0 или а+4=0
а=-3 а=-4