Question

Раскройте модуль в функции

Answer 1

f(x) = 2|x-1| - 5 + x

1) x ≥ 1

f(x) = 2x -2 -5 + x

f(x) = 3x -7

2) x < 1

f(x) = -2x + 2 -5 +x

f(x) = -x -3