Question

Найдите сумму целых решений неравенства:

Answer 1

!!!!!!!!!!!!!!!!!!!!!!

Answer 2

$\sqrt{4x-x^{2} }>x-5\\\\1)\left \{ {{x-5<0} \atop {4x-x^{2}\geq0}} \right. \\\\\left \{ {{x<5} \atop {x(x-4)\leq 0}} \right.$

        +                        -                               +

__________[0]__________[4]______________

                     //////////////////////////

________________________________(5)____

\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

x ∈ [0 ; 4]

$2)\left \{ {{x-5\geq0 } \atop {4x-x^{2}>(x-5)^{2}}} \right.\\\\\left \{ {{x\geq 5} \atop {4x-x^{2}>x^{2}-10x+25}} \right. \\\\\left \{ {{x\geq 5} \atop {4x-x^{2}-x^{2} +10x-25>0 }} \right.\\\\\left \{ {{x\geq5 } \atop {2x^{2}-14x+25>0 }} \right.$

2x² - 14x + 25 =0

D < 0 , решений нет

Окончательный ответ : x ∈ [0 ; 4 ]

0 + 1 + 2 + 3 + 4 = 10