Question

ДАМ 30 БАЛЛОВ!ПОМОГИТЕ!!!
y+2/2+4y−6/7−8−y/14=1
y=(десятичной дробью)

Answer 1

$y + \frac{2}{2} + 4y - \frac{6}{7 } - 8 - \frac{y}{14} = 1 \\y + 4y - \frac{6}{7} - 8 - \frac{y}{14} = 0 \\ 5y - \frac{62}{7} - \frac{y}{14} = 0 \\ 69y - 124 = 0 \\69y = 124 \\ y = \frac{124}{69} = 1 \times \frac{55}{69}$