Question

срочно 15 баллов!срочно

Answer 1

$5\, arccos\, \frac{1}{2}-4\, arcsin(-\frac{\sqrt3}{2})-arcctg\sqrt3=5\cdot \frac{\pi}{3} +4\cdot \frac{\pi }{3}-\frac{\pi }{6}=\\\\=\frac{10\pi +8\pi -\pi }{6}=\frac{17\pi }{6}$