Question

решить уравнение а)36x-8x^2=0
b)5-25x^2=0

Answer 1

$36x-8x^2=0\\9x-2x^2=0\\x(9-2x)=0\\x_1=0\\9-2x_2=0\\2x_2=9\\x_2=\dfrac{9}{2}=4{,}5$

$5-25x^2=0\\1-5x^2=0\\5x^2=1\\x^2=\dfrac{1}{5}\\x= \pm \sqrt{\dfrac{1}{5}}=\pm \dfrac{\sqrt{5}}{5}$

Answer 2

$a)36x - 8 {x}^{2} = 0 \\4x(9 - 2x) = 0 \\4x = 0 \\ x = 0 .\\ 9 - 2x = 0 \\2x = - 9 \\x = - 4.5$
$x_{1} = 0\\x_{2} = - 4.5 \: .$

b) 5x-25x^2=0
5x(1-5x) = 0
5x = 0
x=0
1-5x = 0
-5x=-1
x=0,2 .

x1 = 0
x2= 0,2