Question

8 дробь корень 6+корень 2

Answer 1

8 / (√6 + √2) =

8×(√6 - √2) / (√6 + √2)(√6 - √2) =

8×(√6 - √2) / (6 - 2) =

8×(√6 - √2) / 4 =

2×(√6 - √2) =

2√6 - 2√2

Answer 2

$\frac{8}{ \sqrt{6} + \sqrt{2} } = \frac{8( \sqrt{6} - \sqrt{2} ) }{ (\sqrt{6} + \sqrt{2} )( \sqrt{6} - \sqrt{2} ) } = \frac{8( \sqrt{6} - \sqrt{2)} }{ { \sqrt{6}^{2} - { \sqrt{2} }^{2} } } = \frac{8( \sqrt{6} - \sqrt{2} ) }{6 - 2} = \frac{8( \sqrt{6} - \sqrt{2}) }{4} = 2 (\sqrt{6} - \sqrt{2} ) = 2 \sqrt{6} - 2 \sqrt{2}$