Question

3$log^2 _{8}x+5log x_{8}x=2$

Answer 1

log8 x=t
3t2+5t-2=0
t12= (-5+-корень(25+4*2*3))/6 = (-5+-7).6= -2 1/3
x1=(8)^-2
x2=(8)^1/3=2