Question

(2х+1)^2=2x^2+7 решите уравнение

Answer 1

4x^2+4x+1=2x^2+7

2x^2+4x-6=0

D=b^2-4ac

D=16+48=64

x1=(-b+√D)/2a=(-4+8)/4=1

x2=(-b-√D)/2a=(-4-8)/4=-3