Question

X^2+1/X-4 - X^2-1/X+3 = 23 

Answer 1

$[tex]frac{x^2+1}{x-4}- frac{x^2-1}{x+3}=23 \ ODZ: xneq-3;xneq 4 \ frac{16x^2-25x-275}{(x-4)(x+3)}=0 \ 16x^2-25x-275=0 \ D=18225 = sqrt{135} \ x1=5 \ x2=- frac{55}{16}$