Question

упростить:
5√48-2√75

(3√2+√18)*√2

(4-√5) в квадрате

Answer 1

$5 \sqrt{48} - 2 \sqrt{75} = 20 \sqrt{3} - 10 \sqrt{3} = 10 \sqrt{3}$
$(3 \sqrt{2} + \sqrt{18} ) \times \sqrt{2} = (3 \sqrt{2} + 3 \sqrt{2} ) \times \sqrt{2} = 6 \sqrt{2} \times \sqrt{2} = 6 \times 2 = 12$
$(4 - \sqrt{5} ) {}^{2} = 16 - 8 \sqrt{5} + 5 = 21 - 8 \sqrt{5}$