Question

Развяжите (2/5)^(x+1) (меньше или равно) 1

Answer 1

$(\frac{2}{5} )^{x+1}\leq (\frac{2}{5} )^0\\ \\\frac{2}{5} <1\\ \\x+1\geq 0\\ \\otwet: x\geq -1$

Answer 2

$(\frac{2}{5})^{x+1}\leq 1\\\\(\frac{2}{5})^{x+1}\leq (\frac{2}{5})^0\\\\x+1\geq 0\\\\x\geq -1\\\\Otvet:\; \; x\in [-1,+\infty )\; .$