Question

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tg (arcsin √3/2 + arccos √3/2 + arctg √3 + arcctg (-√3))

Answer 1

$tg(arcsin(\sqrt{3}/2)+arccos(\sqrt{3}/2)+arctan(\sqrt{3})+arcctg(-\sqrt{3}))=\\\\=tg(\frac{\pi}{3}+\frac{\pi}{6}+\frac{\pi}{3}-\frac{\pi}{6})=tg(\frac{2\pi}{3})=tg(\pi-\frac{\pi}{3})=-tg(\pi/3)=-\sqrt{3}$