Question

Решить уравнение 5/(x^2-7x)-(x-5)/(x^2+7x)-9/(x^2-49)=0

Answer 1

$\frac{5}{x^{2}-7x }-\frac{x-5}{x^{2}+7x }-\frac{9}{x^{2}-49 }=0\\\\\frac{5}{x(x-7)}-\frac{x-5}{x(x+7)}-\frac{9}{(x-7)(x+7)}=0\\\\\frac{5x+35-x^{2}+5x+7x-35-9x^{2}}{x(x-7)(x+7)}=0\\\\\frac{-10x^{2}+17x }{x(x-7)(x+7)}=0\\\\x\neq0;x\neq-7;x\neq7\\\\-10x^{2}+17x=0\\\\10x^{2}-17x=0\\\\ x(10x-17)=0\\\\x\neq 0\\\\10x-17=0\\\\10x=17\\\\x=1,7$

Ответ: 1,7