Question

Решите пожалуйста, 34 балла

Answer 1

n+1+2n+3-(3n+4)=3n+4-3n-4=0
${2}^{0} = 1$

Answer 2

(2^(n+1)*2^(2n+3))/(2^(3n+4))=

=(2^n*2*2^2n*2^3)/(2^3n*2^4)=

=(2^n*2^2n*2*8)/2^3n*16)=

=(2^3n*16)/2^3n*16=1