Question

B1 Решить (небольшой)

Answer 1

$\frac{ {x}^{3} \times {x}^{23} }{ ({- x^{4} })^{7} } = \frac{ {x}^{26} }{ - {x}^{28} } = \frac{1}{ - {x}^{2} } = \frac{1}{ - ( - \frac{1}{5} ) ^{2} } = \frac{1}{ - \frac{1}{25} } = - 25$