Question

$\frac{9 {x}^{2} + 6x + 1 }{3x + 1} = \\ \\ \frac{2x - 4}{ {x}^{2} - 4x + 4} =$

Answer 1

ОТВЕТ НА ФОТО
$+ + +$

Answer 2

$\frac{9 {x}^{2} + 6x + 1}{3x + 1} = \frac{(3x + 1)(3x + 1)}{3x + 1} = 3x + 1 \\ \\ \frac{2x - 4}{ {x}^{2} - 4x + 4} = \frac{2(x - 2)}{(x - 2)(x - 2)} = \frac{2}{x - 2}$