Question

Решите уравнение (x^2-x)^2-12(x^2-x)=0

Answer 1

(x²-x)(x²-x-12)=0

(x²-x)(x²-4x+3x-12)=0

x(x-1)(x-4)(x+3)=0

x1=0, x2=1, x3= 4, x4= -3

Answer 2

$( {x}^{2} - x)( {x}^{2} - x - 12) = 0 \\ \\ {x}^{2} - x = 0 \\ {x}^{2} - x - 12 = 0 \\ \\ {x}^{1} = - 3 . \: {x}^{2} = 0. \: {x}^{3} = 1. \: {x}^{4} = 4$