Question

$\sqrt[5]{ {x}^{2} - x - 3 } = - 1$

Answer 1

$\sqrt[5]{{x}^{2} - x - 3 } = - 1 \\ {x}^{2} - x - 3 = - 1 \\ {x}^{2} - x - 2 = 0 \\ (x - 2)(x + 1) = 0 \\ x1 = 2 \\ x2 = - 1$