Question

$( \frac{ {x}^{8} }{ {y}^{ - 5} } ) ^{ - 4} \times ( \frac{ {x}^{ - 4} }{ {y}^{8} } ) ^{ - 10}$

Answer 1

$( \frac{y {}^{ - 5} }{ {x}^{8} } ) {}^{4}*( \frac{ {y}^{8} }{ {x}^{ - 4} } ) {}^{10} = \\ \\ \frac{ {y}^{ - 20} }{ {x}^{32} } * \frac{ {y}^{80} }{x {}^{- 40} } = \\ \\ \frac{ {y}^{60} }{ {x}^{ - 8} } = \\ \\ {y}^{60} {x}^{8} = {x}^{8} {y}^{60}$