Question

помогите с 3 пожалуйста

Answer 1

$\displaystyle\tt \frac{2x^2}{5}-\frac{4x-2}{3}=-0.2x \ \ |\cdot15\\\\ 6x^2-5(4x-2)=-3x\\\\ 6x^2-20x+10+3x=0\\\\ 6x^2-17x+10=0\\\\ D=289-240=49=7^2\\\\ x_1=\frac{17-7}{12}=\frac{10}{12}=\frac{5}{6}\\\\ x_2=\frac{17+7}{12}=\frac{24}{12}=2$