Question

Найдите корни уравнения

Answer 1

$\frac{2x+3}{2}-\frac{x^{2}+6x}{6}=1 \\\frac{6x+9}{6}-\frac{x^{2}+6x}{6}=1$

$\frac{6x+9-x^{2}-6x }{6}=1\\ 6x+9-x^{2}-6x=6\\-x^{2}=-3\\x^{2}=3\\x_{1}=\sqrt{3}\\x_{2}=-\sqrt{3}$