Question

(4х-11) (4х+11) -16в квадрате -7х+41 при х=120

Answer 1

$16 {x}^{2} - 121 - {16}^{2} - 7x + 41 = - 7x - 80 = - 7 \times 120 - 80 = - 840 - 80 = - 920$