Question

512 номер,срочно 28баллов!

Answer 1

а) $y=\sqrt{x^2-5x+6} \\x^2-5x+6\geq 0\\(x-2)(x-3)\geq 0$

x∈(-∞;2]∪[3;+∞)

б) $y=\sqrt{9-x^2} \\9-x^2\geq 0\\x^2-9\leq 0\\(x-3)(x+3)\leq 0$

x∈[-3;3]