Question

Найдите значение алгебраического выражения (-2 18/25)x+y:1 1/6-99z при x=-4 4/17, y=-25 2/3, z=-0,02

Answer 1

$( - 2 \frac{18}{25}) \times ( - 4) + ( - 25 \frac{2}{3} ) \div 1 \frac{1}{6} \\ - 99 \times ( - 0.02) = - 9.14$
$1)( - 2 \frac{18}{25} ) \times ( - 4) = \frac{68}{25} \times 4 = \\ = \frac{272}{25} = 10 \frac{22}{25}$
$2)( - 25 \frac{2}{3} ) \div 1 \frac{1}{6} = - \frac{77}{3} \div \frac{7}{6} = \\ - \frac{77}{3} \times \frac{6}{7} = - 11 \times 2 = - 22$
$3) - 99 \times ( - 0.02) = 1.98$
$4)10 \frac{22}{25} - 22 = 10 \frac{22}{25} - 21 \frac{25}{25} = \\ - 11 \frac{3}{25}$
$5) - 11 \frac{3}{25} + 1.98 \\ = - 11.12 + 1.98 = - 9.14$