Question

A{1;-2}, b{-3;3}, c{4;0}
Найти |a|, |b|, |c|
Y=a+b+2c

Answer 1

|a| = √(1² + (-2)²) = √5

|b| = √((-3)² + 3²) = √18 = 3√2

|c| = √(4² + 0²) = √16 = 4

Y = (1 + (-3) + 2*4; -2 + 3 + 2*0) = (6; 1)

Answer 2

$\vec{a}=(1;-2)\; ,\; \; \vec{b}=(-3;3)\; ,\; \; \vec{b}=(4;0)\\\\|\vec{a}|=\sqrt{1^2+2^2}=\sqrt5\\\\|\vec{b}|=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt2\\\\|\vec{c}|=\sqrt{4^2+0^2}=4\\\\\vec{y}=\vec{a}+\vec{b}+2\vec{c}=(1-3+8\, ;\, -2+3+0)=(6\, ;\, 1)$