Question

$\frac{3-\sqrt{3} }{3+\sqrt{3} }$

Answer 1

$\frac{3 - \sqrt{3} }{3 + \sqrt{3} } \times \frac{3 - \sqrt{3} }{3 - \sqrt{3} } = \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3 }{9 - 3} = \frac{12 - 6 \sqrt{3} }{6} = \frac{6(2 - \sqrt{3} )}{6} = 2 - \sqrt{3}$