Question

sin^2(3pi/4-2x)=1 помогите

Answer 1

$\frac{1 - \cos( \frac{3\pi}{2} - 4x ) }{2} = 1 \\ 1 + \cos(4x) = 2$
$\cos(4x) = 1 \\ 4x = 2\pi \times k \\ x = \frac{\pi \times k}{2}$