Question

y=√x²+2x-80 найти область определения функции

Answer 1

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Answer 2

$y=\sqrt{x^2+2x-80} \\ \\x^2+2x-80\geq 0\\ \\ D=b^2-4ac=4+320=324=18^2\\ \\ x=(-2-18)/2=-10\\ \\ x=(-2+18)/2=8\\ \\+++++[-10]-------[8]++++++++++\\ \\ x\in(oo;-10]U[8;+oo)$