Question

Помогите пожалуйста!

Answer 1

Решение на фото.........

Answer 2

1) y = 14

y'=14' = 0

2) $y=-\frac{1}{3} x\\\\y'=-\frac{1}{3}*x'=-\frac{1}{3}$

3)y = 5x - 1

y' = 5*x' - 1' = 5 * 1 - 0 = 5

4) y = x¹⁶

y' = (x¹⁶)' = 16x¹⁵

5) y = 6x⁷

y' = 6 *(x⁷)' = 6 * 7x⁶ = 42x⁶

6) y = 2x⁸

y' = 2 * (x⁸)' = 2 * 8x⁷ = 16x⁷

7) $y=\frac{1}{x^{5} }=x^{-5}\\\\y'=(x^{-5})'=-5x^{-6} =-\frac{5}{x^{6} }$

8) y = eˣ

y' = (eˣ)' = eˣ

9) $y = lnx\\\\y'=(lnx)'=\frac{1}{x}$

10) y = - 13Cosx

y' = - 13 * (Cosx)' =- 13 * ( - Sinx) = 13Sinx

11)  $y=4tgx-\frac{1}{8}x^{8} \\\\y'=4(tgx)' - \frac{1}{8}(x^{8})'=4*\frac{1}{Cos^{2}x }-\frac{1}{8}*8x^{7}=\frac{4}{Cos^{2}x }-x^{7}$

12) $y=\frac{6}{\sqrt[3]{x} }=\frac{6}{x^{\frac{1}{3} } }=6x^{-\frac{1}{3} }\\\\y'=6*(x^{-\frac{1}{3} })'=6*(-\frac{1}{3}x^{-\frac{4}{3} })=-2x^{-\frac{4}{3} }=-2*\frac{1}{x^{\frac{4}{3} } } =-\frac{2}{\sqrt[3]{x^{4} } }=-\frac{2}{x\sqrt[3]{x} }$