Question

значение производной функции

Answer 1

$y=\sqrt[3]{(x-3)^{4} } -\frac{3}{2x^{3} -3x+1}=(x-3)^{\frac{4}{3} }-\frac{3}{2x^{3}-3x+1 }\\\\y'=\frac{4}{3}(x-3)^{\frac{1}{3} }*(x-3)'-\frac{3'*(2x^{3}-3x+1)-3*(2x^{3}-3x+1)'}{(2x^{3} -3x+1)^{2} }=\frac{4\sqrt[3]{x-3} }{3}-\frac{-3*(6x^{2}-3) }{(2x^{3}-3x+1)^{2}}=\frac{4\sqrt[3]{x-3} }{3}+\frac{9(2x^{2}-1) }{(2x^{3}-3x+1)^{2}}$