Question

Помогите с логофмами

Answer 1

Решение во вложении....

Answer 2

$1)\; \; log_{1/3}(x+2)=log_{2}\frac{1}{16}\; \; ,\; \; ODZ:\; \; \; x>-2\\\\log_{1/3}(x+2)=log_22^{-4}\\\\log_{1/3}(x+2)=-4\\\\x+2=(\frac{1}{3})^{-4}\\\\x+2=81\\\\\underline {x=79}\\\\2)\; \; log_{3}(x+1)+log_3(x+3)=1\; ,\; \; \; ODZ:\; \left \{ {{x>-1} \atop {x>-3}} \right. \; \to \; \; x>-1\\\\log_3(x+1)(x+3)=log_33\\\\(x+1)(x+3)=3\\\\x^2+4x+3=3\\\\x^2+4x=0\\\\x(x+4)=0\\\\x_1=0\in ODZ\; ,\; \; x_2=-4\notin ODZ\\\\Otvet:\; \; x=0\; .$