Question

2cos 6x - корень из 2 =0
помогите срочноооо

Answer 1

cos6x=sqr(2)/2
6x=arccos(sqr(2)/2)=+-(pi/4) +2*pi*n
x=+-(pi/24)+pi*n/3

Answer 2

$2Cos6x-\sqrt{2}=0\\\\2Cos6x=\sqrt{2} \\\\Cos6x=\frac{\sqrt{2} }{2}\\\\6x=+-arcCos\frac{\sqrt{2} }{2}+2\pi n,nez \\\\6x=+-\frac{\pi }{4}+2\pi n,nez\\\\x=+-\frac{\pi }{24}+\frac{\pi n }{3},nez$