Предмет: Физика, автор: ДаНиЛа555LOL

Ледокол массой 6000 т, идущий с выключенным двигателем
со скоростью 8 м/с, наталкивается на неподвижную льдину массой
10000 т и движет ее впереди себя. Определить скорость ледокола
после столкновения.

Ответы

Автор ответа: vladyandymokk13

По закону сохранения импульса:

р(до) = р(после)

m1v1 + m2v2 = (m1 + m2)v - над v ставим векторы

v2 = 0, т.к. льдина неподвижная

Находим проекции:

m1v1 + 0 = (m1 + m2)v

6000т = 6 * 10⁶ кг

10000т = 10⁷ кг

v = m1v1 / m1 + m2 = 6 * 10⁶ * 8 / 6 * 10⁶ + 10⁷ = 4,8 * 10⁷ / 1,6 * 10⁷ = 3 м/с

Ответ: 3 м/с

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